4x/x-3+72/x^2-9-4x/x+3

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Solution for 4x/x-3+72/x^2-9-4x/x+3 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

72/(x^2)-((4*x)/x)+(4*x)/x-9-3+3 = 0

72/(x^2)+(4*x)/x-((4*x)/x)-9-3+3 = 0

72/(x^2)+(4*x)/x-9-4-3+3 = 0

72*x^-2 = 9 // : 72

x^-2 = 1/8

-2 < 0

1/(x^2) = 1/8 // * x^2

1 = 1/8*x^2 // : 1/8

8 = x^2

x^2 = 8 // ^ 1/2

abs(x) = 2*2^(1/2)

x = 2*2^(1/2) or x = -(2*2^(1/2))

x in { 2*2^(1/2), -(2*2^(1/2)) }

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